A sheet of rubber is stretched out over a ring of radius 0.25 m. I pour liquid
Question:
A sheet of rubber is stretched out over a ring of radius 0.25 m. I pour liquid water at 20◦C on it, as in Fig. P3.205, so that the rubber forms a half sphere (cup). Neglect the rubber mass and find the surface tension near the ring.
H20 Rubber sheet FIGURE P3.205
Step by Step Answer:
Force increases F SL Where L length is the Perimeter 2r ...View the full answer
Fundamentals Of Thermodynamics
ISBN: 9781118131992
8th Edition
Authors: Claus Borgnakke, Richard E. Sonntag
Related Video
The property of the surface of a liquid that allows it to resist an external force, due to the cohesive nature of its molecules. The cohesive forces between liquid molecules are responsible for the phenomenon known as surface tension. The molecules at the surface of a glass of water do not have other water molecules on all sides of them and consequently, they cohere more strongly to those directly associated with them (in this case, next to and below them, but not above). is not really true that a \\\"skin\\\" forms on the water surface; the stronger cohesion between the water molecules as opposed to the attraction of the water molecules to the air makes it more difficult to move an object through the surface than to move it when it is completely submersed
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