A glass tumbler containing 243 cm 3 of air at 1.00 10 2 kPa (the barometric
Question:
A glass tumbler containing 243 cm3 of air at 1.00 × 102 kPa (the barometric pressure) and 20°C is turned upside down and immersed in a body of water to a depth of 25.5 m. The air in the glass is compressed by the weight of water above it. Calculate the volume of air in the glass, assuming the temperature and barometric pressure have not changed.
Step by Step Answer:
Calculate the mass of 1 cm 2 of the 205 m of water above the air in the ...View the full answer
Related Video
In this video, the concept of pressure has been explained. The bottle is filled up with water, remove the pipe, and now you can see the clear flow of water from the holes due to liquid pressure.You can see that the second layer is holding the weight of the first layer and the third layer holding the weight of both upper layers, that’s why liquid flows out wider from the third as compared to the first two.At the first hole, water doesn’t roll along the walls; it flows out at an angle.At the second hole, you’ll see that the water flows out at a wider angle as compared to the first hole.At the third hole, we can see that the flow of water is much wider/greater than the other holes.This proves that the pressure at the bottom of the bottle is much more than the pressure at the top layers. P = ????gh
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