Determine the number of ideal stages required in Example 7.4 if the solvent rate used is twice the minimum.

Data From Example 7.4:-

A solution of acetic acid (C) in water (A) is to be extracted using isopropyl ether (B) as the solvent. The feed is 1000 kg/h of a solution containing 35 wt% acid and 65 wt% water. The solvent used is essentially pure isopropyl ether. The exiting raffinate stream should contain 2 wt% acetic acid. Operation is at 293 K and 1 atm. Determine:

(a) The minimum amount of solvent which can be used and

(b) the number of theoretical stages if the solvent rate used is 60% above the minimum. Table 7.2 gives the equilibrium data.

Data From Table 7.2:-

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Table 7.2 Water-Isopropyl Ether-Acetic Acid Equilibrium Dataa Water phase, wt% Water Ether Acetic acid Isopropyl ether phase, wt% Water Ether Acetic acid 98.10 1.2 0.69 0.5 99.3 0.18 97.10 1.5 1.41 0.7 98.9 0.37 95.50 1.6 2.89 0.8 98.4 0.79 91.70 1.9 6.42 1.0 97.1 1.93 84.40 2.3 13.30 1.9 93.3 4.82 71.10 3.4 25.30 3.9 84.7 11.40 58.90 4.4 36.70 6.9 71.5 21.60 45.10 10.6 44.30 10.8 58.1 31.10 37.10 16.5 46.40 15.1 48.7 36.20