Suppose the return type for the baseDMA::operator=() function were defined as void instead of baseDMA &.What effect,
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Suppose the return type for the baseDMA::operator=() function were defined as void instead of baseDMA &.What effect, if any, would that have? What if the return type were baseDMA instead of baseDMA &?
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There is no effect The baseDMA type is a reference type and t...View the full answer
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