Question: The following code checks for adjacent ones in an n-bit vector. With blocking assignments this code produces the desired logic function, which is f =

The following code checks for adjacent ones in an n-bit vector.

always @(A) begin f = A[1] & A[0]; for (k = 2;

With blocking assignments this code produces the desired logic function, which is f = a1a0 +· · ·+an−1an−2. What logic function is produced if we change the code to use non-blocking assignments?

always @(A) begin f = A[1] & A[0]; for (k = 2; k

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