Given that for the path 1 2 3, a system absorbs 100 kJ as heat

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Given that for the path 1 – 2 – 3, a system absorbs 100 kJ as heat and does 60 kJ work.

While along the path 1 – 4 – 3, it does 20 kJ work (see figure). The heat absorbed during the cycle 1 – 4 – 3 is :

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(a) – 140 kJ

(b) – 80 kJ

(c) – 40 kJ

(d) + 60 kJ

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