Question: You can find the kth smallest element in a BST in O(n) time from an inorder iterator. For an AVL tree, you can find it

You can find the kth smallest element in a BST in O(n) time from an inorder iterator. For an AVL tree, you can find it in O(log n) time. To achieve this, add a new data field named size in AVLTreeNode to store the number of nodes in the subtree rooted at this node. Note the size of a node v is one more than the sum of the sizes of its two children. Figure 26.12 shows an AVL tree and the size value for each node in the tree.

25 ) size: 6 20) size: 2 34) size: 3 5) size:

25 ) size: 6 20) size: 2 34) size: 3 5) size: 1 30) size: 1 (50 ) size: 1

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import javautilScanner public class Exercise2605 public static void mainString args AVLTree2 tree new AVLTree2 Scanner input new ScannerSystemin SystemoutprintEnter 15 numbers for int i 0 i 15 i treei... View full answer

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