Show that if (mu_{i}=mu+alpha_{i}) and (mu) is the mean of the (mu_{i}), it follows that [sum_{i=1}^{k} n_{i}
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Show that if \(\mu_{i}=\mu+\alpha_{i}\) and \(\mu\) is the mean of the \(\mu_{i}\), it follows that
\[\sum_{i=1}^{k} n_{i} \alpha_{i}=0\]
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Ali Khawaja
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Related Book For 
Probability And Statistics For Engineers
ISBN: 9780134435688
9th Global Edition
Authors: Richard Johnson, Irwin Miller, John Freund
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