Question: Explain what the following code prints. Draw a picture of the linked list after each step. LinkedList staff = new LinkedList (); staff.addFirst(Harry); staff.addFirst(Diana); staff.addFirst(Tom);
Explain what the following code prints. Draw a picture of the linked list after each step.
LinkedList staff = new LinkedList<>();
staff.addFirst("Harry");
staff.addFirst("Diana");
staff.addFirst("Tom");
System.out.println(staff.removeFirst());
System.out.println(staff.removeFirst());
System.out.println(staff.removeFirst());
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LinkedList staff new LinkedList Since the linked list allocates the memory run time Nothing is allocated here But only a linked list of named staff is ... View full answer
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