A is an m x n matrix with a singular value decomposition A = UV T ,

A is an m x n matrix with a singular value decomposition A = UΣV^T, where U is an m x m orthogonal matrix, Σ is an m x n "diagonal" matrix with r positive entries and no negative entries, and V is an n x n orthogonal matrix. Justify each answer.

Justify the statement in Example 2 that the second singular value of a matrix A is the maximum of ΙΙAxΙΙ as x varies over all unit vectors orthogonal to v₁, with v₁ a right singular vector corresponding to the first singular value of A.

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EXAMPLE 2 Let A be the matrix in Example 1. Since the eigenvalues of ATA are 360, 90, and 0, the singular values of A are 0₁ = √360 = 6√10, ₂= √90=3√10, 03=0 From Example 1, the first singular value of A is the maximum of || Ax|| over all unit vectors, and the maximum is attained at the unit eigenvector v₁. Theorem 7 in Section 7.3 shows that the second singular value of A is the maximum of || Ax|| over all unit vectors that are orthogonal to v₁, and this maximum is attained at the second unit eigenvector, V2 (Exercise 22). For the v₂ in Example 1, 4 Av₂ = - [ 11 14 -2 -2/3 -1/3=[-