The efficiency of a screw jack is maximum when (a) (alpha=frac{pi}{4}-frac{phi}{2}) (b) (alpha=frac{pi}{4}+frac{phi}{2}) (c) (frac{pi}{2}-frac{phi}{2}) (d) (frac{pi}{2}+frac{phi}{2})
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The efficiency of a screw jack is maximum when
(a) \(\alpha=\frac{\pi}{4}-\frac{\phi}{2}\)
(b) \(\alpha=\frac{\pi}{4}+\frac{\phi}{2}\)
(c) \(\frac{\pi}{2}-\frac{\phi}{2}\)
(d) \(\frac{\pi}{2}+\frac{\phi}{2}\)
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