Question: Using (mathbf{w}) and (mathbf{X}) as defined in the previous exercise, show that ((mathbf{X} mathbf{w})^{top}=mathbf{w}^{top} mathbf{X}^{top}) by multiplying out both sides.

Using \(\mathbf{w}\) and \(\mathbf{X}\) as defined in the previous exercise, show that \((\mathbf{X} \mathbf{w})^{\top}=\mathbf{w}^{\top} \mathbf{X}^{\top}\) by multiplying out both sides.

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