Question: (Y) is a random variable that can take any positive integer value. The likelihood of these outcomes is given by the Poisson pdf [p(y)=frac{lambda^{y}}{y!} exp
\(Y\) is a random variable that can take any positive integer value. The likelihood of these outcomes is given by the Poisson pdf
\[p(y)=\frac{\lambda^{y}}{y!} \exp \{-\lambda\}\]
By using the fact that, for a discrete random variable, the pdf gives the probabilities of the individual events occurring and that probabilities are additive,
(a) compute the probability that \(Y \leq 4\) for \(\lambda=5\), i.e. \(P(Y \leq 4)\).
(b) Using the result of (a) and the fact that one outcome has to happen, compute the probability that \(Y>4\). (one of the two events, \(Y \leq 4\) and \(Y>4\), has to happen.)
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