Question: Show that if we use the loss function L(o) in Exercise 9, then the loss-to-node gradient can be computed for the final layer ht as

Show that if we use the loss function L(o) in Exercise 9, then the loss-to-node gradient can be computed for the final layer ht as follows:

∂L(o)

∂ht

= UT ∂L(o)

∂o The updates in earlier layers remain similar to Exercise 9, except that each o is replaced by L(o). What is the size of each matrix ∂L(o)

∂hp

?

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