Question: In a triangle ABC, AB = 6, BC = 8 and AC = 10. A perpendicular dropped from B, meets in side AC at D.

In a triangle ABC, AB = 6, BC = 8 and AC = 10.

A perpendicular dropped from B, meets in side AC at D. A circle of radius BD (with center B) is drawn. If the circle cuts AB and BC at P and Q, respectively, then AP:QC is equal to:

(a) 1:1

(b) 3:2

(c) 4:1

(d) 3:8

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