Question: Figure Q2(a) shows an active filter circuit. Vi R= 10k CH= 0.1 F 46 -1 (1) RE190KQ +9V A -9V RH=10kQ R= 10kn R=

Figure Q2(a) shows an active filter circuit. Vi R= 10k CH= 0.1 F 46 -1 (1) RE190KQ +9V A -9V RH=10kQ R= 10kn

Figure Q2(a) shows an active filter circuit. Vi R= 10k CH= 0.1 F 46 -1 (1) RE190KQ +9V A -9V RH=10kQ R= 10kn R= 10kn C=0.002 F T RF2=90k +9V -9V Figure Q2(a) Calculate the overall effective gain of the circuit in decibels. Vo (6 marks) Determine the lower cut-off frequency and upper cut-off frequency. (6 marks)

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