Verify the second equality in (2.32), again by using the linearity of expectations. (2.32) Cov[X, Y] =
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Verify the second equality in (2.32), again by using the linearity of expectations.
(2.32)
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Cov[X, Y] = E[XY] – E[X]E[ Y] = E[Xx³] – E[X]E[X²]=0 + 0 · 1 = 0.
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