Question: Find the function f (x,y) whose differential is df = (x + y) 1 dx + (x + y) 1 dy and which has the

Find the function f (x,y) whose differential is

df = (x + y)−1dx + (x + y)−1dy

and which has the value f(1,1) = 0. Do this by performing a line integral on a rectangular path from (1,1) to (x1,y1) where x1 > 0 and y1 > 0.

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