If a hydrogen atom is in a 2s state, the probability of finding the electron at a
Question:
If a hydrogen atom is in a 2s state, the probability of finding the electron at a distance r from the nucleus is proportional to 4Πr2Ψ22swhere Ψ represents the orbital (wave function):
where a0 is a constant known as the Bohr radius, equal to 0.529 × 10-10m.
(a) Locate the maxima and minima of Ψ2s.
(b) Draw a rough graph of Ψ2s.
(c) Locate the maxima and minima of Ψ22s.
(d) Draw a rough graph of Ψ22s.
(e) Locate the maxima and minima of 4Πr2Ψ22s.
(f) Draw a rough graph of 4Πr2Ψ22s.
Transcribed Image Text:
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a To find the extrema we omit the constant factor We cancel the exponential factor which is the same ...View the full answer
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