In Example 4.8 we analyzed the case of a bead on a rotating parabolic wire. The energy
Question:
In Example 4.8 we analyzed the case of a bead on a rotating parabolic wire. The energy of the bead was not conserved, but the Hamiltonian was:
There is an equilibrium point at \(r=0\) which is unstable if \(\omega>\omega_{0} \equiv \sqrt{2 g} \alpha\), neutrally stable if \(\omega=\omega_{0}\), and stable if \(\omega
Data from Example 4.8
Fantastic news! We've Found the answer you've been seeking!
Step by Step Answer:
Related Book For
Question Posted: