Question: The energy difference between the lowest electronic state ({ }^{1} S_{0}) and the first excited state ({ }^{3} S_{1}) of the helium atom is (159,843

The energy difference between the lowest electronic state \({ }^{1} S_{0}\) and the first excited state \({ }^{3} S_{1}\) of the helium atom is \(159,843 \mathrm{~cm}^{-1}\). Evaluate the relative fraction of the excited atoms in a sample of helium gas at a temperature of \(6000 \mathrm{~K}\).

Step by Step Solution

3.36 Rating (152 Votes )

There are 3 Steps involved in it

1 Expert Approved Answer
Step: 1 Unlock

The relative fraction of the excited atoms in t... View full answer

blur-text-image
Question Has Been Solved by an Expert!

Get step-by-step solutions from verified subject matter experts

Step: 2 Unlock
Step: 3 Unlock

Students Have Also Explored These Related Mechanics Questions!