Using the Lorentz transformations of the (mathbf{E}) and (mathbf{B}) fields, show that (mathbf{E} cdot mathbf{B}) is a
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Using the Lorentz transformations of the \(\mathbf{E}\) and \(\mathbf{B}\) fields, show that \(\mathbf{E} \cdot \mathbf{B}\) is a Lorentz invariant; that is, show that \(\mathbf{E}^{\prime} \cdot \mathbf{B}^{\prime}=\mathbf{E} \cdot \mathbf{B}\).
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