Question: Let E inc = e 0 E 0 exp[i(kz t)] be the electric field of a planewave propagating in a homogeneous dielectric medium. The

Let Einc = e0E0 exp[i(kz − ωt)] be the electric field of a planewave propagating in a homogeneous dielectric medium. The wave vector k = nk0 = nω/c, where n is the index of refraction
of the medium. Suppose that the number density of scatters increases from N to N + δN in a thin layer of the medium between z = 0 and z = δt. Because δt is infinitesimal, Einc scatters once from every extra atom in the layer. Therefore, if the atomic scattering amplitude is f(θ,φ), the extra electric field produced at the distant observation point z >> δt is

Erad (2) 8N Eo8t = o [dr layer exp(ik R) R 10

(a) Change variables to η = R/z, integrate by parts, and compare the original integral to the new integral in the limit kz >> 1. Note that f(0) ≡ f(θ = 0, φ) does not depend on φ and establish that

Z - St R -ko 0 -f(0, p).

(b) Construct E(z) = Einc(z) + Erad(z) from the results of part (a) and argue that your expression remains valid at z = δt. Derive from this fact an expression for δk/δN, the change in wave vector induced by the density perturbation. Integrate and conclude that the index of refraction of the unperturbed medium satisfies

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Erad (2) 8N Eo8t = o [dr layer exp(ik R) R 10 Z - St R -ko 0 -f(0, p).

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