Question: A function y = y(x) satisfies the equation with y = 1 when x = 0. By repeated differentiation, show that y (n) (0) =

A function y = y(x) satisfies the equation

dy dx =y-x+1

with y = 1 when x = 0. By repeated differentiation, show that y(n)(0) = 1 (n ≥ 2), and find the Maclaurin series for y.

dy dx =y=x+1

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