Consider again the can shown in Figure 8.40. Allowing for an overlap of 6mm top and bottom

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Consider again the can shown in Figure 8.40. Allowing for an overlap of 6mm top and bottom surfaces to give a rim of 3mm on the can, show that the area A mm2 of metal used is given by

A(d) = n(d + 3.6d+ 1.44)/2 + 2000/d

where d cm is the diameter of the can. Show that the value of d* which minimizes the area of the can satisfies the equation

(d + 1.8) = 2000

Calculate d* and the corresponding value of the height of the can.

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