Show that the solutions of z 4 3z 2 + 1 = 0 are given by
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Show that the solutions of z4 – 3z2 + 1 = 0 are given by z = 2 cos 36°, 2 cos 72°, 2 cos 216°, 2 cos252° Hence show that
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(a) cos 36 =(5 + 1) (b) cos 72 =(5 - 1) 4
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