A cosmic ray proton approaches Earth vertically at the equator, where the horizontal component of Earths magnetic field is 3 5 x 10 5 T If the proton is moving at 3 0 x10 6 m s, what is the ratio of the magnetic force to the gravitational force on the proton

Question: A cosmic-ray proton approaches Earth vertically at the equator, where the horizontal component of Earths magnetic field is 3.5 x 10 - 5 T. If

A cosmic-ray proton approaches Earth vertically at the equator, where the horizontal component of Earth’s magnetic field is 3.5 x 10^-⁵ T. If the proton is moving at 3.0 x10⁶ m/s, what is the ratio of the magnetic force to the gravitational force on the proton?

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