Question: With inertial systems S and S' arranged with their corresponding axes parallel and S' moving in the +x direction, it was apparent that the Lorentz

With inertial systems S and S' arranged with their corresponding axes parallel and S' moving in the +x direction, it was apparent that the Lorentz transformation for y and z would be y' = y and z' = z. The transformation for the y and z components of the momentum are not so apparent, however. Show that, as stated in Equations 2-16 and 2-17, p'_y = p_y and p'_z = p_z.

P = Y(Px vE/c) E' = y(E-vpx) P'y = Py Pz =

P 2-16

P = Y(Px vE/c) E' = y(E-vpx) P'y = Py Pz = P 2-16

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