Question: We have three dice, each with numbers x = 1, ..., 6, and with probabilities as follows: die 1: p(x)=1/6, die 2: p(x) = (7

We have three dice, each with numbers x = 1, ..., 6, and with probabilities as follows:

die 1: p(x)=1/6, die 2: p(x) = (7 − x)/21, die 3: p(x) = x2/91. A die is selected at random, tossed, and the number 4 appears. What is the probability that it is die 2 that was tossed?

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