Show that at normal incidence on the boundary between two dielectrics, as n_ti S → 1, R → 0, and T → 1. Moreover, prove that as n_ti → 1, R → 0, and T → 1 Moreover, prove that as  n_ti → 1, R_|| → 0, R_⊥ → 0, T_|| → 1, and T_⊥ → 1 for all θ_t. Thus as the two media take on more similar indices of refraction, less and less energy is carried off in the reflected wave. It should be obvious that when n_ti = 1 there will be no interface and no reflection.