Question: A (2-mathrm{kg}) block moving at (4 mathrm{~m} / mathrm{s}) hits a slower (1-mathrm{kg}) block moving at (2 mathrm{~m} / mathrm{s}). If the (2-mathrm{kg}) block continues
A \(2-\mathrm{kg}\) block moving at \(4 \mathrm{~m} / \mathrm{s}\) hits a slower \(1-\mathrm{kg}\) block moving at \(2 \mathrm{~m} / \mathrm{s}\). If the \(2-\mathrm{kg}\) block continues in the same direction at \(3 \mathrm{~m} / \mathrm{s},(a)\) what is the speed of the slower block?
(b) Is the collision elastic?
(c) By what factor does the internal energy of the system change?
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Analyzing the Block Collision We can solve this problem using the concepts of momentum and conservation of mechanical energy assuming the collision is ... View full answer
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