A (5-mathrm{kg}) object is subject to an interaction that has a potential energy (U(x)=frac{1}{2} k x^{2}-b x),
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A \(5-\mathrm{kg}\) object is subject to an interaction that has a potential energy \(U(x)=\frac{1}{2} k x^{2}-b x\), where \(k=2.0 \mathrm{~J} / \mathrm{m}^{2}\) and \(b=1.5 \mathrm{~J} / \mathrm{m}\). At \(x=1.0 \mathrm{~m}\), the object is found to be moving to the left at \(4 \mathrm{~m} / \mathrm{s}\). What is the speed of the object at \(x=2.0 \mathrm{~m}\) ? What is the object's kinetic energy at \(x=3.0 \mathrm{~m}\) ?
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To find the speed of the object at x 20 textm we can use the conservation of mechanical energy At an...View the full answer
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