Question: A capacitor connected to a battery initially holds a charge of (+q) on its positive plate and (-q) on its negative plate. The electric field

A capacitor connected to a battery initially holds a charge of \(+q\) on its positive plate and \(-q\) on its negative plate. The electric field between the plates is initially \(\vec{E}\). A dielectric material is then inserted that polarizes in such a way as to produce an electric field of \(-0.50 \vec{E}\) (where the - sign indicates that this field opposes the initial field \(\vec{E}\) ). Determine the new charge stored on the positive plate.

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