Question: A capacitor for which (mathrm{C}=10 mathrm{mF}) is connected across an AC source. The source emf is given by (mathscr{E}=mathscr{E}_{max } sin omega t), with (varepsilon_{max

A capacitor for which $\mathrm{C}=10 \mathrm{mF}$ is connected across an AC source. The source emf is given by $\mathscr{E}=\mathscr{E}_{\max } \sin \omega t$, with $\varepsilon_{\max }=5.0 \mathrm{~V}$ and $\omega=20 \mathrm{~s}^{-1}$.

(a) What is the amplitude of the current through the capacitor?

(b) How does the current amplitude change as you increase the source angular frequency?

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