Question: A force (vec{F}=F_{x} hat{imath}+F_{y} hat{jmath}) with (F_{x}=3.0 mathrm{~N}) and (F_{y}=2.0 mathrm{~N}) is exerted on a particle that undergoes a displacement (vec{D}=D_{x} hat{imath}+D_{y} hat{jmath}) with (D_{x}=2.0
A force \(\vec{F}=F_{x} \hat{\imath}+F_{y} \hat{\jmath}\) with \(F_{x}=3.0 \mathrm{~N}\) and \(F_{y}=2.0 \mathrm{~N}\) is exerted on a particle that undergoes a displacement \(\vec{D}=D_{x} \hat{\imath}+D_{y} \hat{\jmath}\) with \(D_{x}=2.0 \mathrm{~m}\) and \(D_{y}=-2.0 \mathrm{~m}\).
(a) Determine the work done by the force on the particle.
(b) What is the angle between \(\vec{F}\) and \(\vec{D}\) ?
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To determine the work done by the force on the particle we use the formula textWork vecF cdot vecD G... View full answer
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