Question: A pendulum is released from an elevation of (1.15 mathrm{~m}) and allowed to swing in a room filled with (1.50 times 10^{21}) nitrogen molecules having
A pendulum is released from an elevation of \(1.15 \mathrm{~m}\) and allowed to swing in a room filled with \(1.50 \times 10^{21}\) nitrogen molecules having an average speed of \(550 \mathrm{~m} / \mathrm{s}\). If the energy of the pendulum is equal to the energy distributed over all the nitrogen molecules, what is the pendulum's mass? The mass of a nitrogen molecule \(\left(\mathrm{N}_{2}\right)\) is \(4.65 \times 10^{-26} \mathrm{~kg}\).
Step by Step Solution
There are 3 Steps involved in it
To find the mass of the pendulum we need to equate its energy to the energy distributed over all the nitrogen molecules in the room The energy of the ... View full answer
Get step-by-step solutions from verified subject matter experts
