Question: A positively charged infinite sheet has a surface charge density of (+5.0 mathrm{nC} / mathrm{m}^{2}). What is (a) the electric field at a distance (0.10

A positively charged infinite sheet has a surface charge density of $+5.0 \mathrm{nC} / \mathrm{m}^{2}$. What is

(a) the electric field at a distance $0.10 \mathrm{~m}$ from the sheet and

(b) the potential difference between two points located at distances of $0.30 \mathrm{~m}$ and $0.50 \mathrm{~m}$ from the sheet?

(c) $\mathrm{A}+3.0 \mathrm{nC}$ charged particle is initially at a distance $0.50 \mathrm{~m}$ from the sheet. How much work must an external force do to move this particle to a distance of $0.30 \mathrm{~m}$ from the sheet?

(d) Taking the potential to be zero at the sheet, at what distances from the sheet are the equipotential surfaces having potential of magnitudes $20 \mathrm{~V}, 40 \mathrm{~V}$, and $60 \mathrm{~V}$ ?

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a To find the electric field at a distance of 010 m from the sheet we can use the formula for the electric field due to an infinite sheet of charge E fracsigma2epsilon0 where E is the electric field s... View full answer

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