A positron with laboratory energy 50 GeV interacts with the atomic electrons in a lead target to
Question:
A positron with laboratory energy 50 GeV interacts with the atomic electrons in a lead target to produce μ+μ− pairs. If the cross-section for this process is given by
σ = 4πα2h̅2c2/3E2CM,
calculate the positron’s effective interaction length. The density of lead is 1.14 × 107 kg/m3.
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The total centreofmass energy is given by E CM 2mc 2 E L 12 023 GeV a...View the full answer
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