Question: A positron with laboratory energy 50 GeV interacts with the atomic electrons in a lead target to produce + pairs. If the

A positron with laboratory energy 50 GeV interacts with the atomic electrons in a lead target to produce μ⁺μ⁻ pairs. If the cross-section for this process is given by

σ = 4πα²h̅²c²/3E²_CM,

calculate the positron’s effective interaction length. The density of lead is 1.14 × 10⁷ kg/m³.

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The total centreofmass energy is given by E CM 2mc 2 E L 12 023 GeV a... View full answer

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