An electron in an old-fashioned television picture tube is accelerated, at a constant rate, from (2.0 times
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An electron in an old-fashioned television picture tube is accelerated, at a constant rate, from \(2.0 \times 10^{5} \mathrm{~m} / \mathrm{s}\) to \(1.0 \times 10^{7} \mathrm{~m} / \mathrm{s}\) in a 12 -mm-long "electron gun."
(a) What is the acceleration of the electron?
(b) What time interval is needed for the electron to travel the length of the gun?
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