Question: For a certain interaction, the potential energy in joules is given by (U(x)=a x+b x^{2}), where (a=+4.0 mathrm{~J} / mathrm{m}) and (b=-2.0 mathrm{~J} / mathrm{m}^{2}).
For a certain interaction, the potential energy in joules is given by \(U(x)=a x+b x^{2}\), where \(a=+4.0 \mathrm{~J} / \mathrm{m}\) and \(b=-2.0 \mathrm{~J} / \mathrm{m}^{2}\). If, at some instant, a \(10-\mathrm{kg}\) object taking part in this interaction has an \(x\) component of velocity of \(-3.0 \mathrm{~m} / \mathrm{s}\) and a position \(x=+2.0 \mathrm{~m}\), and moves in one dimension only. What is its speed
(a) at \(x=+1.0 \mathrm{~m}\) andÂ
\((b)\) at \(x=-1.0 \mathrm{~m}\) ?
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To find the speed of the object at different positions x well use the conservation of mechanical energy The mechanical energy E of the object at any p... View full answer
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