If pp annihilation at rest proceeds via S-states, explain why the reaction pp 0
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If pp̅ annihilation at rest proceeds via S-states, explain why the reaction pp̅ → π0π0 is forbidden as a strong or electromagnetic interaction.
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The initial state has L 0 and hence using 536 its parity is P i P p P p 1 L 1 In ...View the full answer
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