Question: Suppose (q) is outside the irregularly shaped surface in Figure 24.26. Show that the electric flux due to (q) through the closed surface is zero.

Suppose $q$ is outside the irregularly shaped surface in Figure 24.26. Show that the electric flux due to $q$ through the closed surface is zero. (Draw a small wedge from $q$ through the surface and determine the electric flux through the two intersections between the wedge and the surface.)

Figure 24.26 Formal proof of Gauss's law. (a) spherical Gaussian surface 1

Figure 24.26 Formal proof of Gauss's law. (a) spherical Gaussian surface 1 spherical Gaussian surface 2, irregular surface wedge dA dA, dA (b) dA: intersection of wedge and spherical Gaussian surface 2 dA: intersection of wedge dA, and irregular surface dA: intersection of wedge and spherical Gaussian surface 1 dA di E

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