Question: When a wire (1.0 mathrm{~m}) long carries a (20-mathrm{A}) current in the (+x) direction in a uniform external magnetic field, the magnetic force exerted by

When a wire \(1.0 \mathrm{~m}\) long carries a \(20-\mathrm{A}\) current in the \(+x\) direction in a uniform external magnetic field, the magnetic force exerted by the field on the wire is given by \(F_{x}^{B}=0, F_{y}^{B}=3.0 \mathrm{~N}, F_{z}^{B}=2.0 \mathrm{~N}\). When the wire is rotated until the charge carriers travel in the \(+y\) direction, the magnetic force exerted by the field on the wire is given by \(F_{x}^{B}=-3.0 \mathrm{~N}, F_{y}^{B}=0, F_{z}^{B}=-2.0 \mathrm{~N}\). What is the magnetic field?

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