Question: Wires A, B, C, D, and E meet at a junction point O. The current in wire (mathrm{D}) and (mathrm{E}) is twice as in wire
Wires A, B, C, D, and E meet at a junction point O. The current in wire \(\mathrm{D}\) and \(\mathrm{E}\) is twice as in wire \(\mathrm{A}\) and four times as in \(\mathrm{C}\), respectively. The current in wire \(\mathrm{A}\) is \(4.2 \mathrm{~mA}\) into the junction, and the current in wire \(\mathrm{C}\) is \(5.6 \mathrm{~mA}\) out of the junction. What is the current in wire \(\mathrm{B}\), and in what direction-into or out of the junction-is the current?
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To solve this problem we can apply Kirchhoffs current law which states that the sum of currents ent... View full answer
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