Question: You measure a quantity (T) that can be represented as (=2 pi sqrt{frac{l}{g}}). If (T) and (l) have the units of seconds and meters, respectively,

You measure a quantity $T$ that can be represented as $=2 \pi \sqrt{\frac{l}{g}}$. If $T$ and $l$ have the units of seconds and meters, respectively, then what should the units of $g$ be for the expression to be correct?

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