Question: 6.10 For any p > 0, let Kp be the kernel de ned over R+ R+ by Kp(x; y) = e????(x+y)p : (6.25) Show

6.10 For any p > 0, let Kp be the kernel de ned over R+  R+ by Kp(x; y) = e????(x+y)p

: (6.25)

Show that Kp is positive de nite symmetric (PDS) i p  1. (Hint: you can use the fact that if K is NDS, then for any 0 <  1, K is also NDS.)

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