Question: A curve has the equation y = e 2 x ln x. Show that the equation of the tangent at the point with x-coordinate
A curve has the equation y = e2x − ln x. Show that the equation of the tangent at the point with x-coordinate 1 is y = (2e2 − 1)x − e2 + 1.
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dy dx 2ex 1 x At x 1 y ... View full answer
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