Solve the following equations, in the intervals given. a sin 20 = sin 0, 00 2
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Solve the following equations, in the intervals given.
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a sin 20 = sin 0, 0≤0 ≤ 2π c 3 cos 20 = 2 cos² 0, 0≤ 0 < 360° 0 e 3 cos 0 -sin-1 = 0, 0≤ 0 < 720° g 2 sin = sec 0,0 ≤ 0 ≤ 2π i 2 tan 0 = √3(1 − tan 0)(1 + tan ), 0≤ 0 ≤ 2π k 4 tan 0 tan 20, 0≤ 0 ≤ 360° b cos 20 1- cos 0, -180° < 0 ≤ 180° d sin 40 cos 20, 0≤ 0 ≤ T f cos²0 sin 20 = sin² 0, 0≤ 0 ≤ T h 2 sin 20 = 3 tan 0, 0≤ 0 < 360° j sin²0 = 2 sin 20, -180° < 0 < 180°
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A sin20 sin0 00 2 We can use the trigonometric identity sin 20 2 sin0 cos0 So 2 sin 0 cos0 sin0 This gives us two possible solutions sin 0 0 or cos0 1 ...View the full answer
Related Book For
Pearson Edexcel A Level Mathematics Pure Mathematics Year 2
ISBN: 9781292183404
1st Edition
Authors: Greg Attwood, Jack Barraclough, Ian Bettison, David Goldberg, Alistair Macpherson, Joe Petran
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