Calculate the vapor pressure of water droplets of radius 1.00 10 8 m at 360. K
Question:
Calculate the vapor pressure of water droplets of radius 1.00 × 10−8 m at 360. K in equilibrium with water vapor. Use the tabulated value of the density and the surface tension at 298 K from Appendix B for this problem.
Step by Step Answer:
We first calculate the vapor pressure of water at 298 K us...View the full answer
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The property of the surface of a liquid that allows it to resist an external force, due to the cohesive nature of its molecules. The cohesive forces between liquid molecules are responsible for the phenomenon known as surface tension. The molecules at the surface of a glass of water do not have other water molecules on all sides of them and consequently, they cohere more strongly to those directly associated with them (in this case, next to and below them, but not above). is not really true that a \\\"skin\\\" forms on the water surface; the stronger cohesion between the water molecules as opposed to the attraction of the water molecules to the air makes it more difficult to move an object through the surface than to move it when it is completely submersed
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