Question: In this problem, we consider the calculations for Ï p and Ï x for the particle in the box shown in Figure 17.5 in more
In this problem, we consider the calculations for Ïpand Ïxfor the particle in the box shown in Figure 17.5 in more detail. In particular, we want to determine how the absolute uncertainty Îpxand the relative uncertainty Îpx/pxof a single peak corresponding to either the most probable positive or negative momentum depends on the quantum number n.
a. First we must relate k and px. From E = p2x/2m and E = n2h2/8ma2, show that px = nh/2a.
b. Use the result from part (a) together with the relation linking the length of the box and the allowed wavelengths to obtain px = hk.
c. Relate Î px and Îpx /px with k and Îk.
d. The following graph shows £Ak£2 versus k k peak . By plotting the results of Figure 17.5 in this way, all peaks appear at the same value of the abscissa. Successive curves have been shifted upward to avoid overlap. Use the width of the £Ak£2 peak at half height as a measure of Îk. What can you conclude from this graph about the dependence of Îpx on n?

e. The following graph shows £Ak£2 versus k /n for n = 3, n = 5, n = 7, n = 11, n = 31, and n = 101. Use the width of the £Ak£2 peak at half height as a measure of Îk /n. Using the graphs, determine the dependence of Îpx /px on n. One way to do this is to assume that the width depends on n like (Îpx /px) = nα, where α is a constant to be determined. If this relationship holds, a plot of ln (Îpx /px) versus ln n will be linear and the slope will give the constant α.

Figure 17.5

n=101 n=31 n=11 n=7 n=5 n=3 0.5 -1.0 -0.5 1.0 (k-kpeak)/(1010 m-1) Key: n=3 n=5 n=7 n=11 n=31 n=101 6 x 108 kln (m-') 4 x 108 8 x 108 1 x 109 2.
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